SOLUTION: still having problems helping my son, please help. the problem is 3/2d2 + 4/3d
the examples in the book are not very clear to myself or my son
Thankyou theodore uzonyi
Algebra.Com
Question 142369: still having problems helping my son, please help. the problem is 3/2d2 + 4/3d
the examples in the book are not very clear to myself or my son
Thankyou theodore uzonyi
Answer by ptaylor(2198) (Show Source): You can put this solution on YOUR website!
We want to get a "Lowest Common Denominator (LCD)" for these two fractions. The LCD is the smallest number that both 2d^2 and 3d will divide evenly into. By inspection, we can see that the LCD is 6d^2. We'll now multiply each term by 6d^2/6d^2 (which equals 1) and when we do that we will have reduced the expression to one fraction instead of two. When we do this we get:
Hope this helps---ptaylor
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