SOLUTION: Can you help me solve this one?......I have to divide this...
Page 292
Number6
49x^8-35x^6-56x^3
----------- ----
7x^3
Algebra.Com
Question 141350This question is from textbook Beginning Algebra
: Can you help me solve this one?......I have to divide this...
Page 292
Number6
49x^8-35x^6-56x^3
----------------
7x^3
This question is from textbook Beginning Algebra
Answer by nabla(475) (Show Source): You can put this solution on YOUR website!
49x^8-35x^6-56x^3
----------------
7x^3
=7x^5-5x^3-8
check by multiplication:
(7x^5-5x^3-8)7x^3=49x^8-35x^6-56x^3
RELATED QUESTIONS
I need help solving some very complex problems that I do not understand.
Add... (answered by Canti)
Factor
7x^2+56x
I think that this would end up being 49x+56x which would be 105x
(answered by stanbon)
I still need some assistance with these problems, the ones I think I have right I wrote... (answered by oberobic)
Can you please help me solve this? I have to divide using long division.... (answered by jim_thompson5910)
Can you help me on this one...??? I have to divide, leave the answer in exponent form.... (answered by edjones)
I have to combine if possible...Do not use a calculator or a table of square roots...Can... (answered by Alan3354)
Can you please help me solve this problem?... (answered by stanbon)
I have to completely factor 2abx-14ax-8bx+56x. Can someone help me work this one out.... (answered by edjones)
Hi there can you help me solve this problem?..... I have to subtract it....THANKS!!!!... (answered by nabla)