You can
put this solution on YOUR website!Tracy leaves for work at 8:a.m traveling at 36 mph. Sarah finds that Tracy has forgotten her briefcase, so she leaves 8:05 chasing after her at 50 mph. At what time will Sarah catch tracy?
:
Change 5 min to hrs: 5/60 =
hrs
Let t = travel time (in hrs), for T to catch up with S
:
When T catches up with S, there will have traveled the same distance
Write a distance equation from this fact: Dist = speed * time
:
T's dist = S's distance
50t = 36(t+
)
50t = 36t +
50t - 36t = 3
14t = 3
t =
change to minutes and fractional minutes to seconds
60 *
= 12.857 min = 12 min 51 sec
:
8:05 + 12 min 51 sec = 08:17:51 AM, when T catches up with S
:
:
Check solution on calc by finding the distances
36(
) =
36 * .297 = 10.7 mi
:
50 *
= 10.7 mi
