SOLUTION: Divide: x2 � 9x + 20 � x2 � 16 3x � 15 9x + 36

Question 135843: Divide:
x2 � 9x + 20 � x2 � 16
3x � 15 9x + 36

Answer by AlexxsDad(4) (Show Source): You can put this solution on YOUR website!
I think you may have mis-typed the second problem. I don't see what's being divided. But I will help you with the first problem. Your problem is:
{x^2 - 9x + 20} / {x^2 - 16}
This is best solved by factoring both sides.
First the dividend (the left side): X^2 - 9x + 20 = {x-4}{x-5}
Then the divisor: {x^2 - 16} = {x+4}{x-4}
(this one is "difference of squares" factoring)
So once factored, your original problem is re-written as such:
{{x-4}{x-5}} / {{x+4}{x-4}}
Clearly, the {x-4} cancels on both sides, leaving the answer: {x-5} / {x+4}
RELATED QUESTIONS
2. Divide: x2 � 9x + 20 � x2 � 16 3x � 15 9x + 36 (answered by jim_thompson5910)

2. Divide: x2 � 9x + 20 � x2 � 16 3x � 15/x%^29x + 36 (answered by checkley71)

Divide: (x2 � 9x + 20)/(3x � 15) divided by (x2 � 16)/(9x + 36)... (answered by checkley71)

May I have this answer checked as well? I am not feeling confident within my... (answered by solver91311)

Divide x^2 � 9x + 20/ 3x � 15 � x^2 � 16/9x + 36 (answered by stanbon)

x2+9x+20=0 (answered by checkley71)

x2 + 9x =... (answered by mastermath)

Factor completely: x2 � 9x + 20 (answered by wuwei96815)

Factor completely: x2 � 9x + 20 (answered by checkley77)