SOLUTION: i am trying to help my daughter with how to simplify rational expressions and i am stuck on this question. 2x2 - 3x - 9 (over/ divided by) 2x2 - 18 (times) x2 + x - 6 (over/ divid

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Question 134835: i am trying to help my daughter with how to simplify rational expressions and i am stuck on this question.
2x2 - 3x - 9 (over/ divided by) 2x2 - 18 (times) x2 + x - 6 (over/ divided by) 2x2 - x -6. The only part i'm not quite sure about is the 2x2-18.
Found 2 solutions by solver91311, stanbon:
Answer by solver91311(24713)   (Show Source): You can put this solution on YOUR website!
Looks like you are dealing with:



And I take it that you get the idea that you need to factor each of the polynomials so that you can eliminate common factors in the numerators and denominators.

To factor , first factor out a 2:

is the difference of two squares, and factors like , or in this case:

Therefore the entire factorization is:

I think that is what you were looking for. Write back if you need more help.

Good luck,
John


Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
[(2x^2 - 3x - 9)/ (2x^2 - 18)]
Factor where you can:
= [(2x+3)(x-3)/2(x-3)(x+3)] * [(x+3)(x-2)/(2x+3)(x-2)]
Cancel factors common to num. and denom.: (2x+3),(x+3).(x-3),(x-2)
= [1/2] * [1/1]
= 1/2
=============
Cheers,
Stan H.


=
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