SOLUTION: I could really use some help with this: Solve the problem: p(x)+-0.002x�+1.2x-300 Thanks in advance

Question 134241: I could really use some help with this:
Solve the problem:
p(x)+-0.002x�+1.2x-300
Thanks in advance
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
p(x)+-0.002x�+1.2x-300
:
I assume you mean:
p(x) = -.002x^2 + 1.2x - 300
:
It looks like this equation has no real roots, check the discriminate (b^2 - 4ac)
a = -.002; b = 1.2; c = 300
:
1.2^2 - 4 * -.002 * -300 =
1.44 - 2.4 = -.96 indicates there is no real roots for this equation

RELATED QUESTIONS
2x^2+9x+4=0 I could really use some help with this... (answered by scott8148)

Hi, I could really use some help with this problem: Find the equation of the line (answered by aaaaaaaa)

graph the equation {{{ y = x - 1}}} I am not sure where to begin and end with this... (answered by Alan3354)

Hello I could really use some help with this problem: Solve by completing the square.... (answered by nerdybill)

Hi, I could really use some help with this problem: Find a number such that one... (answered by Fermat)

2x2+9x+4=0 I could really use some help with this... (answered by Fombitz)

Hi again, I could use some help with this problem: Solve the logarithmic equation:... (answered by Nate)

http://i.imgur.com/awhGZBa.png Hello! My problem is log[1/4](1/1024) = x... (answered by Alan3354)

I could really use some help with this equation: {{{ -0.4=b/1.6 }}} what would b equal?... (answered by josh_jordan)