SOLUTION: Decompose into a partial fraction 6x^2-15x+16/x^3-3x^2+4x I know to start I need to factor the denominator, but I'm not sure how to go about that.

Question 133408This question is from textbook College Algebra with Trigonometry
: Decompose into a partial fraction
6x^2-15x+16/x^3-3x^2+4x
I know to start I need to factor the denominator, but I'm not sure how to go about that. This question is from textbook College Algebra with Trigonometry

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Decompose into a partial fraction
6x^2-15x+16/x^3-3x^2+4x
I know to start I need to factor the denominator, but I'm not sure how to go about that.
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Factoring the denominator:
x^3-3x^2+4x= x(x^2-3x+4)
Factoring x^2-3x+4
x = [3 +- sqrt(9-4*4)]/2
x = [3 +- sqrt(-5)]/2
x = (3/2) + (i/2)sqr(5) or x = (3/2) - (i/2)sqrt(5)
Comment:
I don't believe this is the answer you want. That
denominator should be x^3-3x^2-4x.
---------------
Cheers,
Stan H.
=========================
Cheers,
Stan H.
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