SOLUTION: Find a third degree polynomial f(x), which has roots 2, 1-2i and which has y-intercept 2 (ie, f(0) =2).

Question 133139: Find a third degree polynomial f(x), which has roots 2, 1-2i and which has y-intercept 2 (ie, f(0) =2).
Answer by vleith(2983) (Show Source): You can put this solution on YOUR website!
You are given two root. One of those roots is imaginary. So there is another imaginary root.
roots are 2, 1-2i, 1+2i

multiply to get

What is f(0)?
= -6
We want f(0) to be 2. So we need to divide our function by -3.

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