SOLUTION: I've been working through factoring polynomials and have solved the following as such; However, my solution doesn't match the one given could you please rectify my solution. Than

Question 131306: I've been working through factoring polynomials and have solved the following as such; However, my solution doesn't match the one given could you please rectify my solution. Thank you.
n^6+(n-1)^3=(n^2+n-1)[(n^2+n-1)(n^2+n-1)]
=(n^2+n-1)(n^4+n^3-n^2+n^3+n^2-n-n^2-n+1)
=(n^2+n-1)(n^4+2n^3-n^2-2n+1)
I keep getting the same answer and I can't get the solution given which is
(n^2+n-1)(n^4-n^3+2n^2-2n+1)
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
n^6+(n-1)^3=(n^2+n-1)[(n^2+n-1)(n^2+n-1)]
---------
The way you have posted the problem it is not true.
You have [(n^2)^3 + (n-1)^3] = [n^2+(n-1)]^3
That is not true.
Cheers,
Stan H.

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