SOLUTION: Can you help me with this problem? The product of two consecutive integers is 360. Find the integers. I got to (x-18)(x+20)=0, but then I got confused Thanks!

Question 131064: Can you help me with this problem?
The product of two consecutive integers is 360. Find the integers.
I got to (x-18)(x+20)=0, but then I got confused
Thanks!
Found 2 solutions by checkley71, stanbon:
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
LET X & X+1 BE THE 2 INTEGERS.
X(X+1)=360
X^2+X-360=0
USING THE QUADRATIC EQUATION i GET X=18.48 & -19.48.
DON'T THINK THIS IS THE ANSWER.
-------------------------------------------------------------
HOWEVER IF YOU'RE LOOKING FOE 2 CONSECUTIVE EVEN INTEGERS THEN:
X(X+2)=360
X^2+2X-360=0
(X+20)(X-18)=0
X=20=0
X=-20 ANSWER. WITH X+2=-18 ANSWER.
X-18=0
X=18 ANSWER. WITH X+2=20 ANSWER.

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The product of two consecutive integers is 360. Find the integers.
--------------------
I think you need consecutive EVEN integers.
---------------------
1st: 2x
2nd: 2x+2
------------
EQUATION:
2x*(2x+2) = 360
4x^2+4x-360 = 0
x^2 + x -90 = 0
x = [-1 +- sqrt(1-4*-90)]/2
x = [-1 +- sqrt(361)]/2
x = [-1 +- 19]/2
x = [18/2] or [-20/2]
x = 9 or -10
---------------
2x = 18 and 2x+2 = 20
OR
2x -20 and 2x+2 = -18
=========================
Cheers,
Stan H.

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