SOLUTION: 3a^2+12ab+12b^2 can you show me how this is done completely
Factoring Trinomials
#2 8x^2-26x-15
Thank you
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Question 131011: 3a^2+12ab+12b^2 can you show me how this is done completely
Factoring Trinomials
#2 8x^2-26x-15
Thank you
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
# 1
Start with the given expression
Factor out the GCF
Now let's focus on the inner expression
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Looking at we can see that the first term is and the last term is where the coefficients are 1 and 4 respectively.
Now multiply the first coefficient 1 and the last coefficient 4 to get 4. Now what two numbers multiply to 4 and add to the middle coefficient 4? Let's list all of the factors of 4:
Factors of 4:
1,2
-1,-2 ...List the negative factors as well. This will allow us to find all possible combinations
These factors pair up and multiply to 4
1*4
2*2
(-1)*(-4)
(-2)*(-2)
note: remember two negative numbers multiplied together make a positive number
Now which of these pairs add to 4? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 4
| First Number | Second Number | Sum | | 1 | 4 | 1+4=5 |
| 2 | 2 | 2+2=4 |
| -1 | -4 | -1+(-4)=-5 |
| -2 | -2 | -2+(-2)=-4 |
From this list we can see that 2 and 2 add up to 4 and multiply to 4
Now looking at the expression , replace with (notice adds up to . So it is equivalent to )
Now let's factor by grouping:
Group like terms
Factor out the GCF of out of the first group. Factor out the GCF of out of the second group
Since we have a common term of , we can combine like terms
So factors to
So this also means that factors to (since is equivalent to )
note: is equivalent to since the term occurs twice. So also factors to
------------------------------------------------------------
So our expression goes from and factors further to
------------------
Answer:
So factors to
# 2
Looking at we can see that the first term is and the last term is where the coefficients are 8 and -15 respectively.
Now multiply the first coefficient 8 and the last coefficient -15 to get -120. Now what two numbers multiply to -120 and add to the middle coefficient -26? Let's list all of the factors of -120:
Factors of -120:
1,2,3,4,5,6,8,10,12,15,20,24,30,40,60,120
-1,-2,-3,-4,-5,-6,-8,-10,-12,-15,-20,-24,-30,-40,-60,-120 ...List the negative factors as well. This will allow us to find all possible combinations
These factors pair up and multiply to -120
(1)*(-120)
(2)*(-60)
(3)*(-40)
(4)*(-30)
(5)*(-24)
(6)*(-20)
(8)*(-15)
(10)*(-12)
(-1)*(120)
(-2)*(60)
(-3)*(40)
(-4)*(30)
(-5)*(24)
(-6)*(20)
(-8)*(15)
(-10)*(12)
note: remember, the product of a negative and a positive number is a negative number
Now which of these pairs add to -26? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to -26
| First Number | Second Number | Sum | | 1 | -120 | 1+(-120)=-119 |
| 2 | -60 | 2+(-60)=-58 |
| 3 | -40 | 3+(-40)=-37 |
| 4 | -30 | 4+(-30)=-26 |
| 5 | -24 | 5+(-24)=-19 |
| 6 | -20 | 6+(-20)=-14 |
| 8 | -15 | 8+(-15)=-7 |
| 10 | -12 | 10+(-12)=-2 |
| -1 | 120 | -1+120=119 |
| -2 | 60 | -2+60=58 |
| -3 | 40 | -3+40=37 |
| -4 | 30 | -4+30=26 |
| -5 | 24 | -5+24=19 |
| -6 | 20 | -6+20=14 |
| -8 | 15 | -8+15=7 |
| -10 | 12 | -10+12=2 |
From this list we can see that 4 and -30 add up to -26 and multiply to -120
Now looking at the expression , replace with (notice adds up to . So it is equivalent to )
Now let's factor by grouping:
Group like terms
Factor out the GCF of out of the first group. Factor out the GCF of out of the second group
Since we have a common term of , we can combine like terms
So factors to
So this also means that factors to (since is equivalent to )
------------------------------------------------------------
Answer:
So factors to
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