SOLUTION: Please help me with this problem I am not sure how to solve it. I tried it and can't get it. Please help me. Solve the following problem involving applications of polynomials.

Question 130294: Please help me with this problem I am not sure how to solve it. I tried it and can't get it. Please help me.
Solve the following problem involving applications of polynomials.
Three consecutive even integers are such that the square of the third is 76 more than the square of the second. Find the three integers.

Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
X, X+2, X+4 ARE THE 3 CONSECUTIVE EVEN INTEGERS.
(X+4)^2=(X+2)^2+76
X^2+8X+16=X^2+4X+4+76
8X-4X=80-16
4X=64
X=64/4
X=16 ANSWER FOR THE SMALLER INTEGER.
16+2=18 THE MIDDLE INTEGER.
16+4=20 THE LARGEST INTEGER.
20^2=18^2+76
400=324+76
400=400

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