SOLUTION: I have 2 problems that I am stumped on
x^2-xy/y times y^2/2x-2y how do I cancel the GCF
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[(x^2-xy)/y]*[y^2/
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Question 129035: I have 2 problems that I am stumped on
x^2-xy/y times y^2/2x-2y how do I cancel the GCF
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[(x^2-xy)/y]*[y^2/(2x-2y)]
[x(x-y)/y]*[y^2/2(x-y)] now cancel out the (x-y) & one of the y terms.
x*y/2=xy/2 answer.
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
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