SOLUTION: Someone please help me with this problem! It involves a little geometry as well as algebra I suppose. A rectangle is 5 cm longer than it is wide. If its length and width are b

Question 126347This question is from textbook Algebra
: Someone please help me with this problem! It involves a little geometry as well as algebra I suppose.
A rectangle is 5 cm longer than it is wide. If its length and width are both increased by 3 cm, its area is increased by 60 cm^2. Find the dimensions of the original rectangle.
I tried to set it up by combining terms to get the equation x^2 + 24 = y + 60 but that produced answers that didn't seem to check.
If you can, please help me out! This question is from textbook Algebra

Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Let = original area
Let = original width
Let = original length

from above

The dimensions of the original rectangle are 6 x 11 cm2
check

OK
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