# SOLUTION: A rectangle is 4 times as long as it is wide. A second rectangle is 5 centimenters longer and 2 centimeters wider than the first. The area of the second rectangle is 270 square ce

Algebra ->  Algebra  -> Polynomials-and-rational-expressions -> SOLUTION: A rectangle is 4 times as long as it is wide. A second rectangle is 5 centimenters longer and 2 centimeters wider than the first. The area of the second rectangle is 270 square ce      Log On

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 Click here to see ALL problems on Polynomials-and-rational-expressions Question 126055: A rectangle is 4 times as long as it is wide. A second rectangle is 5 centimenters longer and 2 centimeters wider than the first. The area of the second rectangle is 270 square centimeters greater than the first. What are the deminsions of the original rectangle? Thank you in advance!!Answer by scott8148(6628)   (Show Source): You can put this solution on YOUR website!let x=width, so 4x=length (x+2)(4x+5)=(x)(4x)+270 __ 4x^2+13x+10=4x^2+270 13x=260