# SOLUTION: I am just trying to check over my answer to this question. I have that it is PRIME so therefore the polynomial is NOT factorable. The equation in question is 10-9y-2y^2

Algebra ->  Algebra  -> Polynomials-and-rational-expressions -> SOLUTION: I am just trying to check over my answer to this question. I have that it is PRIME so therefore the polynomial is NOT factorable. The equation in question is 10-9y-2y^2      Log On

 Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations! Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!

 Algebra: Polynomials, rational expressions and equations Solvers Lessons Answers archive Quiz In Depth

 Question 123501: I am just trying to check over my answer to this question. I have that it is PRIME so therefore the polynomial is NOT factorable. The equation in question is 10-9y-2y^2Answer by stanbon(57377)   (Show Source): You can put this solution on YOUR website!The equation in question is 10-9y-2y^2 ----------------------- Rearrange: -2y^2-9y+10 y = [9 +- sqrt(81-4*-2*10)]/(-4) y = [9 +- sqrt(161)]/(-4) y = (-9/4) -(1/4)sqrt(161) or y = (-9/4)+(1/4)sqrt(161) (y+[(+9/4)+(1/4)sqrt(161)])(y+[(9/4)+(-1/4)sqrt(161)]) ------------- These are factors of the polynomial but I would not disagree with you; the polynomial is prime by most normal standards. --------- Cheers, Stan H.