SOLUTION: Given that one zero is 9, find the other zeros for this polynomial fucntion: {{{f(x)=x^3-14x^2+47x-18}}}

Question 122575: Given that one zero is 9, find the other zeros for this polynomial fucntion:

Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
f(x)=x^3-14x^2+47x-18
x^3-14x^2+47x-18/x-9=x^2-5x+2 Long division.
x^2-5x+2=0

Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=17 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 4.56155281280883, 0.43844718719117. Here's your graph:

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