SOLUTION: Three consecutive even integers are such that the square of the third is 76 more than the square of the second. Find the three integers

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Question 122437: Three consecutive even integers are such that the square of the third is 76 more than the square of the second. Find the three integers
Answer by solver91311(24713)   (Show Source): You can put this solution on YOUR website!


If the first even integer is n, the second is n + 2, and the third is n + 4.


We are given that 


Expand the binomials, collect terms, and solve for n









So the first even integer is 16, the second is 18, and the third is 20.



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