SOLUTION: Boyle's law applied to the amount of gas used in a given experiment at a constant temp., states the pV=240 where p is pressure measured in kilopascals and V is volume measured in c
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Question 121890This question is from textbook 
:  Boyle's law applied to the amount of gas used in a given experiment at a constant temp., states the pV=240 where p is pressure measured in kilopascals and V is volume measured in cubic centimeters. If a decrease in pressure of 1 kPa produces an increase in volume of 20cm^3, what was the original pressure on the gas?
i have:
pV=240
240-1=20
i dont think that is right...i dont get how to set up the problem though
 
This question is from textbook 
Answer by scott8148(6628)   (Show Source): You can put this solution on YOUR website!
 pV=240 __ V=240/p
pV=(p-1)(V+20) __ pV=pV+20p-V-20 __ 0=20p-V-20
substituting for V __ 0=20p-(240/p)-20
multiplying by p __ 0=20p^2-20p-240 __ dividing by 20 __ 0=p^2-p-12
factoring __ 0=(p-4)(p+3) 
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