SOLUTION: how do i divide these two problems: y^2-12y+20 /y-2 and 2x^2+7x+3 / 2x+1 i need the steps for these two problems by today january 21,2008 at 8:00pm please

Question 121615: how do i divide these two problems:

y^2-12y+20 /y-2

and 2x^2+7x+3 / 2x+1

i need the steps for these two problems by today january 21,2008 at 8:00pm

please its urgent
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
y^2-12y+20 /y-2
Factor to get:
= [(y-2)(Y-10)]/(y-2
= y-10
=========================================
2x^2+7x+3 / 2x+1
Factor to get:
= [2x^2+6x+x+3]/(2x+1)
= [2x(x+3)+(x+3)]/(2x+1
= [(x+3)(2x+1)]/(2x+1)
----------------
Comment:
Are you sure that denominator is not 2x+1 ?
------------------
Well, you say it is 2x+1 so you can cancel the 2x+1 in numerator and denominator to get:
= x+3
=================
Cheers,
Stan H.

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