SOLUTION: In class, we derived that \frac{1}{n(n + 1)} = \frac{1}{n} - \frac{1}{n + 1}. Fill in the blanks to make a true equation: \frac{5x}{(x - 1)(x^2 + 2)(x + 7)^3)} = \frac{A}{x

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Question 1209392: In class, we derived that
\frac{1}{n(n + 1)} = \frac{1}{n} - \frac{1}{n + 1}.
Fill in the blanks to make a true equation:
\frac{5x}{(x - 1)(x^2 + 2)(x + 7)^3)} = \frac{A}{x - 1} + \frac{Bx + C}{x^2 + 2} + \frac{D}{x + 7} + \frac{E}{(x + 7)^2} + \frac{F}{(x + 7)^3}
Answer by Edwin McCravy(20059)   (Show Source): You can put this solution on YOUR website!
Since there are no blanks, perhaps you meant to find values of A thru F that
would make this equation an identity.



This is a very complicated partial fraction problem.
Go to this site: 

https://www.symbolab.com/solver/partial-fractions-calculator

input this 

and you'll get:



If your teacher expects you to do this by hand, then your teacher should
be fired.  This is NOT teaching mathematics!

This is extremely more complicated than the very simple problem of breaking
 
 

into partial fractions and getting:



Edwin
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