SOLUTION: If four out of five doctors prefer fast food, then at a convention of 445 doctors, how many prefer fast food?

Question 120856: If four out of five doctors prefer fast food, then at a convention of 445 doctors, how many prefer fast food?
Found 2 solutions by checkley71, stanbon:
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
4/5=.8
.8*445=356 doctors prefer fast foods.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Let "x" be the number that prefer fast food.
x/445 = 4/5
x = (4/5)445
x = 4*89
x = 356
---------------
Cheers,
Stan H.
RELATED QUESTIONS
. Fast food. If four out of five doctors prefer fast food, then at a convention of 445... (answered by stanbon)
Fast Food. If four out of five doctors prefer fast food, then at a convention of 445... (answered by nerdybill)
Fast food. If four out of five doctors prefer fast food, then at a convention of 445... (answered by checkley77)
Fast food. If four out of five doctors prefer fast food, then at a convention of 445... (answered by dabanfield)
If four out of five doctors prefer fast food, then at a convention of 445 doctors how... (answered by ewatrrr)
Please help me If four out of five doctors prefer fast food,then at a convention of 445... (answered by jim_thompson5910)
If four out of five doctors prefer fast food, then at a convention of 445 doctors, how... (answered by stanbon)
If four out of five doctors prefer fast food, then at a convention of 445 doctors, how... (answered by ptaylor)
If four out of five doctors prefer fast food, then at a convention of 445 doctors, how... (answered by rfer)