If [x+(1/3)] or [x-(-1/3)] were a factor then the factorization would be
Then would give a zero of .
So to find out, we use synthetic division to see if the remainder, which is the
same value as when -1/3 is substituted for x, is zero. That happens when the
last term on the bottom right of the synthetic division is 0. So here goes the
synthetic division:
Be sure to remember that has a missing term in
. So we must consider it as
-1/3 | 3 1 0 -3 1
| -1 0 0 1
3 0 0 -3 2
The number on the bottom right did not turn out to be zero. It came out to be
2 instead, so, no [x + (1/3)] is not a factor of .
Edwin