SOLUTION: 4 ___ 3n + 2 ___ n+1 + 2 ___ n^2+n

Algebra.Com
Question 120832: 4
___
3n
+
2
___
n+1
+
2
___
n^2+n

Answer by ankor@dixie-net.com(22740)   (Show Source): You can put this solution on YOUR website!
Assume you mean:
+ +
:
Factor out n in the 3rd denominator:
+ +
:
The common denominator will be: 3n(n+1), so we have:
:
= = =
:
The (n+1)'s cancel, we are left with:

:
How about this? Could you follow this ok? Any questions? Let me know.

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