SOLUTION: I have tried to figure out this equation, can you help me please? Find all values of x such that y=0 y= 1/5x+5

SOLUTION: I have tried to figure out this equation, can you help me please? Find all values of x such that y=0 y= 1/5x+5 - 3/x+1 + 7/5

Question 120765This question is from textbook College Algebra
: I have tried to figure out this equation, can you help me please?
Find all values of x such that y=0
y= 1/5x+5 - 3/x+1 + 7/5 This question is from textbook College Algebra

Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
0=1/(5X+5)-3/(X+1)+7/5
0=[5(X+1)-3*5(5X+5)+7(5X+5)(X+1)]/[5(5X+5)(X+1)] CROSS MULTIPLYING ELIMINATES THE DENOMINATOR. THUS WE HAVE:
(5X+5)-15(5X+5)+7(5X^2+10X+5)=0
5X+5-75X-75+35X^2+70X+35=0
35X^2+35=0
35(X^2+1)=0
X^2+1=0
USING THE QUADRATIC EQUATION:
X=(0+-SQRT0^2-4*1*1)/2
X=(+-SQRT-4)/2
X=(+-2i)/2
X=0+-1i ANSWER.

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