(a) constant term 6; leading coefficient 2. The possible rational zeros are
ANSWER: (plus or minus) 1, 2, 3, 6; 1/2, 3/2
(b) evaluating the polynomial at the possible roots is faster than testing each root using synthetic division. f(3) = 2(27)-3(9)-11(3)+6 = 0, so 3 is a root. Use synthetic division to find the polynomial that remains after the root x=3 is removed.
+----------------
3 | 2 -3 -11 6
| 6 9 -6
+----------------
2 3 -2 0
ANSWER: 3 is a root
(c) The remaining polynomial is
ANSWER: The two other zeros are 1/2 and -2