According to the Remainder theorem, the remainder is the value of the polynomial at x = -6 remainder = 6*(-6)^2 + 31*(-6) - 29 = 1. Next, make these identical transformations 6x^2 + 31x - 29 = (6x^2 + 36x) - (5x + 29) = 6x*(x+6) - (5x+30) + 1 = 6x*(x+6) - 5(x+6) + 1 = (6x-5)*(x+6) + 1. It shows that the quotient is 6x-5 and the remainder is 1. ANSWER
-6 | 6 | 31 | -29 |
-6 | 6 | 31 | -29 |
6 |
-6 | 6 | 31 | -29 |
-36 | |||
6 |
-6 | 6 | 31 | -29 |
-36 | |||
6 | -5 |
-6 | 6 | 31 | -29 |
-36 | 30 | ||
6 | -5 | 1 |