SOLUTION: Factor the polynomial completely, given that hte binomial following it is a factorof the polynomial. x^3+2x^2-5x-6, x+3

Algebra.Com
Question 120066: Factor the polynomial completely, given that hte binomial following it is a factorof the polynomial. x^3+2x^2-5x-6, x+3
Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!

Since is a factor of , is a zero of

So our test zero is -3


Now set up the synthetic division table by placing the test zero in the upper left corner and placing the coefficients of the numerator to the right of the test zero.
-3|12-5-6
|

Start by bringing down the leading coefficient (it is the coefficient with the highest exponent which is 1)
-3|12-5-6
|
1

Multiply -3 by 1 and place the product (which is -3) right underneath the second coefficient (which is 2)
-3|12-5-6
|-3
1

Add -3 and 2 to get -1. Place the sum right underneath -3.
-3|12-5-6
|-3
1-1

Multiply -3 by -1 and place the product (which is 3) right underneath the third coefficient (which is -5)
-3|12-5-6
|-33
1-1

Add 3 and -5 to get -2. Place the sum right underneath 3.
-3|12-5-6
|-33
1-1-2

Multiply -3 by -2 and place the product (which is 6) right underneath the fourth coefficient (which is -6)
-3|12-5-6
|-336
1-1-2

Add 6 and -6 to get 0. Place the sum right underneath 6.
-3|12-5-6
|-336
1-1-20

Since the last column adds to zero, we have a remainder of zero. This means is a factor of

Now lets look at the bottom row of coefficients:

The first 3 coefficients (1,-1,-2) form the quotient




So

You can use this online polynomial division calculator to check your work

Basically factors to

Now lets break down further


Looking at we can see that the first term is and the last term is where the coefficients are 1 and -2 respectively.

Now multiply the first coefficient 1 and the last coefficient -2 to get -2. Now what two numbers multiply to -2 and add to the middle coefficient -1? Let's list all of the factors of -2:



Factors of -2:
1,2

-1,-2 ...List the negative factors as well. This will allow us to find all possible combinations

These factors pair up and multiply to -2
(1)*(-2)
(-1)*(2)

note: remember, the product of a negative and a positive number is a negative number


Now which of these pairs add to -1? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to -1

First NumberSecond NumberSum
1-21+(-2)=-1
-12-1+2=1



From this list we can see that 1 and -2 add up to -1 and multiply to -2


Now looking at the expression , replace with (notice adds up to . So it is equivalent to )




Now let's factor by grouping:


Group like terms


Factor out the GCF of out of the first group. Factor out the GCF of out of the second group


Since we have a common term of , we can combine like terms

So factors to


So this also means that factors to (since is equivalent to )

So factors to

------------------------------------------------------------

Answer:


So factors to

RELATED QUESTIONS

factor polimomial completely, given that the binomial following it is a factorof the... (answered by scott8148)
Factor each polynomial completely given that the binomial following it is a factor of the (answered by tutorcecilia)
Factor each polynomial completely, given that the binomial following it is a factor of... (answered by solver91311,vleith)
Factor the polynomial below completely, given that the binomial following it is a factor... (answered by RAY100)
Factor each polynomial completely, given that the binomial following it is a factor of... (answered by venugopalramana)
46. Factor completely. -3t^3+ 3t^2-6t 60. Factor polynomial completely.... (answered by jim_thompson5910)
Factor each binomial completely given that the second binomial is a factor of the first... (answered by richwmiller)
Please help me to solve the following problem: Factor each polynomial completely,... (answered by Nate)
A) Factor each polynomial completely, given that the binomial following it is a factor of (answered by stanbon)