SOLUTION: factor completely -3t^3+3t^2-6t

Question 119703: factor completely -3t^3+3t^2-6t
Found 2 solutions by scott8148, jim_thompson5910:
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
first, factors common to all terms __ -3t(t^2-t+2)

the remaining trinomial is not factorable
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!

Start with the given expression

Factor out the GCF

Now let's focus on the inner expression

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Looking at we can see that the first term is and the last term is where the coefficients are 1 and 2 respectively.

Now multiply the first coefficient 1 and the last coefficient 2 to get 2. Now what two numbers multiply to 2 and add to the middle coefficient -1? Let's list all of the factors of 2:

Factors of 2:
1,2

-1,-2 ...List the negative factors as well. This will allow us to find all possible combinations

These factors pair up and multiply to 2
1*2
(-1)*(-2)

note: remember two negative numbers multiplied together make a positive number

Now which of these pairs add to -1? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to -1

First Number Second Number Sum
1 2 1+2=3
-1 -2 -1+(-2)=-3

None of these pairs of factors add to -1. So the expression cannot be factored

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Answer:
So factors to

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