SOLUTION: I need your help to solve the following: Divide: (4x^4 - 12x^3 - 48x - 60) + (x

SOLUTION: I need your help to solve the following: Divide: (4x^4 - 12x^3 - 48x - 60) + (x - 4) This question is from a worksheet.

Question 119638: I need your help to solve the following:
Divide: (4x^4 - 12x^3 - 48x - 60) + (x - 4)
This question is from a worksheet.
Found 2 solutions by tangitehewagen, benbjlin:
Answer by tangitehewagen(7) (Show Source): You can put this solution on YOUR website!
I am assuming you mean
Divide: by
If so, then we start by asking what quantity multiplied by results in which we can see is . We then multiply by to get and subtract from which gives us .
So now we want to know what divided by is. We start as in the first step and ask what quantity multiplied by x gives us . The answer to this question is . Multiplying by results in . Subtracting from leaves us with .
The next division is by . As we have done previously, we ask what we need to multiply by to get and find that the quantity would be . Multiplying by gives us and subtracting from gives us .
Finally, we want to know what divided by is. We see that divided by is and multiplying by results in . Subtracting from gives us a remainder of .
Thus divided by .

Answer by benbjlin(6) (Show Source): You can put this solution on YOUR website!
I assume you mean:
(4x^4 - 12x^3 - 48x - 60) / (x - 4)
The most straight forward way is to solve this long division style. We will use 0x^2 as a place holder. As follows:

:::::::::::::::::4*x^3 + 4*x^2 + 16*x + 16 + 4/(x-4)
_____________________________________
(x-4) | 4*x^4 - 12*x^3 - 0*x^2 - 48*x - 60
::::::-(4*x^4 - 16*x^3)
::::::________________
:::::::::::0 4*x^3 - 0*x^2
:::::::::::::::-(4*x^3 - 16*x^2)
:::::::::::::::________________
:::::::::::::::::::0 16*x^2 - 48*x
:::::::::::::::::::::::-(16*x^2 - 64*x)
:::::::::::::::::::::::_______________
:::::::::::::::::::::::::::0 16*x - 60
::::::::::::::::::::::::::::::::-(16*x - 64)
::::::::::::::::::::::::::::::::___________
::::::::::::::::::::::::::::::::::::::::::4
Factor 4 out from: 4x^3 + 4x^2 + 16x + 16 + 4/(x-4)
4*(x^3 + x^2 + 4x + 4 + 1/(x-4))
Check:
1. (x-4)*4*(x^3 + x^2 + 4*x + 4 + 1/(x-4)) Multiply 4 into (x^3...)
2. (x-4) * (4*x^3 + 4*x^2 + 16*x + 16 + 4/(x-4)) Multiply (x-4) into (4*x^3...)
3. 4*x^4 - 16*x^3 + 4x^3 - 16*x^2 + 16*x^2 - 64*x + 16*x - 64 + 4 Simplify
4. 4*x^4 - 12*x^3 - 48*x - 60
RELATED QUESTIONS
For a game, I need to solve the following question: 4(x+3)+2-8(x+4)=2x-3-4(x+2)-60/x... (answered by ramkikk66)
How do I determine the end behavior of the graph of the function? f(x)=-3x^6+2x^4+4x^3-2 (answered by ewatrrr)
3x+4=12x+5 This is what I"ve tried but don't know if I'm right. Plus I need to know... (answered by josgarithmetic,MathTherapy)
I need to solve these quadratic equations using the method that came from India. I am... (answered by solver91311)
(x-4)^3 I got this answer: x^3-12x^2+48x-64 Is that... (answered by stanbon)
I know that it said in the book it involved expressions. This is question 21. off of... (answered by solver91311)
These 3 problems are from a worksheet, not a textbook, and I so desperately need them... (answered by scott8148)
Hi there, I am confronted with the following question: "Solve the inequality and... (answered by longjonsilver)
PLEASE HELP!!! Solve -x^4+200=102x^2. I have to show my work and I don't understand how (answered by Fombitz)