SOLUTION: pleas help me id really apreciate it.
the direction for the problem is to simplfy the equation
x-4 over x squared + 3x divide by x squared - 3x -4 over 2x squared +6x
please h
Algebra.Com
Question 119533: pleas help me id really apreciate it.
the direction for the problem is to simplfy the equation
x-4 over x squared + 3x divide by x squared - 3x -4 over 2x squared +6x
please help:)
Found 2 solutions by stanbon, Denean:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
x-4 divide by x(squared)-3x-4
x(squared) +3x 2x (squared)+ 6x
---------------
Factor where you can to get:
[(x-4)/(x(x+3)] / [(x-4)(x+1)/2x(x+3)]
Cancel (x-4), x, (x+3) leaving you with:
=[1/1]/[(x+1)/2]
Invert the denominator and multiply to get:
= 2/(x+1)
======================
Cheers,
Stan H.
Answer by Denean(2) (Show Source): You can put this solution on YOUR website!
First, you need to understand this is a fraction problem. You need to make all the fractions like. That means the denominators should all be the same. The first two terms' denominators are x^2 or x squared while the third term is 2x^2 or two x squared and the fourth term is 1. You would have to multiply the first and second term by 2 and the fourth term by 2x^2 to make the fractions like.
After making the fractions like, the problem should read like this:
Now add the numerators:
You can also rearrange it:
The numerators should add up to be:
That fraction answer is:
To simplify the problem, divide every term by 2:
This should be the right answer! Thank you for the stimulating problem!
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