SOLUTION: what is the smallest number of cells that need to be coloured in a 5 by 5 square so that any 1 by 4 or 4 by 1 rectangle lying inside the square has at least one cell coloured​.

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: what is the smallest number of cells that need to be coloured in a 5 by 5 square so that any 1 by 4 or 4 by 1 rectangle lying inside the square has at least one cell coloured​.      Log On


   



Question 1192533: what is the smallest number of cells that need to be coloured in a 5 by 5 square so that any 1 by 4 or 4 by 1 rectangle lying inside the square has at least one cell coloured​.
Found 2 solutions by greenestamps, ikleyn:
Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


ANSWER: 7

Obviously, if any row or column contains no colored cells, then you can place a 1x4 or 4x1 rectangle in that row or column without covering any colored cells. So to start with, you need at least 5 of the cells to be colored, with one cell in each column and one cell in each row colored. There are many ways you can do that. As examples....

   +---+---+---+---+---+   +---+---+---+---+---+   +---+---+---+---+---+
   | X |   |   |   |   |   |   | X |   |   |   |   |   |   | X |   |   |
   +---+---+---+---+---+   +---+---+---+---+---+   +---+---+---+---+---+
   |   | X |   |   |   |   | X |   |   |   |   |   | X |   |   |   |   |
   +---+---+---+---+---+   +---+---+---+---+---+   +---+---+---+---+---+
   |   |   | X |   |   |   |   |   | X |   |   |   |   |   |   | X |   |
   +---+---+---+---+---+   +---+---+---+---+---+   +---+---+---+---+---+
   |   |   |   | X |   |   |   |   |   |   | X |   |   |   |   |   | X |
   +---+---+---+---+---+   +---+---+---+---+---+   +---+---+---+---+---+
   |   |   |   |   | X |   |   |   |   | X |   |   |   | X |   |   |   |
   +---+---+---+---+---+   +---+---+---+---+---+   +---+---+---+---+---+

Whatever way you choose those first five cells to be colored, there are four colored cells that are either in row 1 or 5 or in column 1 or 5. That means there are four places you can place a 1x4 or 4x1 rectangle without covering a colored square -- two columns and two rows.

By placing another colored cell at each of the two intersections of those two rows and those two columns, you eliminate all the places where a 1x4 or 4x1 rectangle could have been placed without covering a colored cell. Using the above examples....

   +---+---+---+---+---+   +---+---+---+---+---+   +---+---+---+---+---+
   | X |   |   |   | Y |   |   | X |   |   |   |   |   |   | X |   |   |
   +---+---+---+---+---+   +---+---+---+---+---+   +---+---+---+---+---+
   |   | X |   |   |   |   | X |   |   | Y |   |   | X |   |   |   | Y |
   +---+---+---+---+---+   +---+---+---+---+---+   +---+---+---+---+---+
   |   |   | X |   |   |   |   |   | X |   |   |   |   |   |   | X |   |
   +---+---+---+---+---+   +---+---+---+---+---+   +---+---+---+---+---+
   |   |   |   | X |   |   |   | Y |   |   | X |   |   |   | Y |   | X |
   +---+---+---+---+---+   +---+---+---+---+---+   +---+---+---+---+---+
   | Y |   |   |   | X |   |   |   |   | X |   |   |   | X |   |   |   |
   +---+---+---+---+---+   +---+---+---+---+---+   +---+---+---+---+---+

So the smallest number of colored cells that make any 1x4 or 4x1 rectangle cover at least one colored cell is 5+2=7.



Answer by ikleyn(52803) About Me  (Show Source):
You can put this solution on YOUR website!
.

I managed to solve the problem with the lesser number of colored squares, 6.


   +---+---+---+---+---+ 
   |   |   | X |   |   | 
   +---+---+---+---+---+ 
   |   | X |   |   |   | 
   +---+---+---+---+---+ 
   | X |   |   |   | X | 
   +---+---+---+---+---+  
   |   |   |   | X |   | 
   +---+---+---+---+---+ 
   |   |   | X |   |   | 
   +---+---+---+---+---+ 


ANSWER.     6.