SOLUTION: I'm learning to divide polynomials by polynomials. I have been able to work several problems, but then get stuck as they progress. For example: 25x to the 5th power take away

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Question 119164: I'm learning to divide polynomials by polynomials. I have been able to work several problems, but then get stuck as they progress. For example:
25x to the 5th power take away x to the third power take away 8x take away 2x square divided by 5xsquare take away 4x. I have placed the dividend and divisor in descending order and even tried adding 0x to the fourth power in the dividend. I seem to get the first half correct, but can't get the latter half. What am I doing wrong?
Jennifer

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!
You have done the first steps correctly, that is you put the terms in decending order of degree and put a zero coefficient placeholder in for the missing 4th degree term. I presume you ended up with:

%2825x%5E5%2B0x%5E4-x%5E3-2x%5E2-8x%29%2F%285x%5E2-4x%29

The next step is to factor the denominator. 5x%5E2-4x=x%285x-4%29. Now your problem looks like this:

%2825x%5E5%2B0x%5E4-x%5E3-2x%5E2-8x%29%2Fx%285x-4%29

But notice that there is an x in every term of the numerator which means you can divide through by the x in the denominator to get:

%2825x%5E4%2B0x%5E3-x%5E2-2x-8%29%2F%285x-4%29

Now your polynomial long division shouldn't be so ugly. I don't know how to render the process on this site, so I'll just talk you through it. Write back if you have trouble understanding.

Step 1: 5x goes into 25x%5E4 5x%5E3 times, so 5x%5E3 is the first term of your quotient polynomial.

Step 2: 5x%5E3 times -4 is -20x%5E3 and 5x%5E3 times 5x is 25x%5E4, so 25x%5E4-20x%5E3 is your first partial product.

Step 3: Subtract 25x%5E4-20x%5E3 from the first two terms of the dividend polynomial giving you 0x%5E4%2B20x%5E3.

Step 4: Bring down the next term, -x%5E2 to form your next partial dividend 20x%5E3-x%5E2

Step 6: 5x goes into 20x%5E3 4x%5E2 times, so this is the next term of your quotient polynomial. So far, your quotient should look like 5x%5E3%2B4x%5E2.

Step 7: 4x%5E2 times -4 is -16x%5E2 and 4x%5E2 times 5x is 20x%5E3, so 20x%5E3-16x%5E2 is your next partial product.

Step 8: Subtract this from your previous partial dividend, 20x%5E3-x%5E2 (remembering to change the sign and add when you subtract), to get 0x%5E3%2B15x%5E2.

Step 9: Bring down the next term of the dividend, -2x, to form your next partial dividend, 15x%5E2-2x.

Step 10: 5x goes into 15x%5E2 3x times giving you the next term of your quotient. Your quotient should now look like 5x%5E3%2B4x%5E2%2B3x.

Step 11: 3x times -4 is -12x and 3x times 5x is 15x%5E2, so 15x%5E2-12x is your next partial product.

Step 12: Subtract this from your previous partial dividend, 15x%5E2-2x, resulting in 0x%5E2%2B10x

Step 13: Bring down the last term, -8 to form your next partial dividend 10x-8

Step 14: 5x goes into 10x 2 times, so 2 is the last term of your quotient which should look like 5x%5E3%2B4x%5E2%2B3x%2B2.

Step 15: 2 times -4 is -8 and 2 times 5x is 10x so your next partial product is 10x-8.

Step 16: Subtract. %2810x-8%29-%2810x-8%29=0. There is no remainder, so you are done.

Hope this helps.
John