SOLUTION: the perimeter of a square is 12x^2-8x+4. find the length of one side

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Question 119034: the perimeter of a square is 12x^2-8x+4. find the length of one side
Answer by jim_thompson5910(28545) About Me  (Show Source):
You can put this solution on YOUR website!
Perimeter of a square: P=4S where S is the side length


12x%5E2-8x%2B4=4S Plug in P=12x%5E2-8x%2B4



%2812x%5E2-8x%2B4%29%2F4=cross%284%2F4%29S Divide both sides by 4 to isolate and solve for S



%2812x%5E2%29%2F4-%288x%29%2F4%2B%284%29%2F4=S Simplify and break up the fraction



3x%5E2-2x%2B1=S Divide


So the length of one side is S=3x%5E2-2x%2B1