SOLUTION: A function is given. What is the minimum value of the function? 𝑓(𝑥)=3𝑥^2 −11𝑥+𝐶, 5≤𝑥≤10, 𝐶 is a constant (A)𝑓(5) (B) 𝑓(10) (C) 𝑓(11/3) (D) �

Question 1189469: A function is given. What is the minimum value of the function?
𝑓(𝑥)=3𝑥^2 −11𝑥+𝐶, 5≤𝑥≤10, 𝐶 is a constant
(A)𝑓(5) (B) 𝑓(10) (C) 𝑓(11/3) (D) 𝑓(11/6) (E) none of the above.
Answer by ikleyn(52776) (Show Source): You can put this solution on YOUR website!
.


x-coordinate of the vertex is  x = "  " =  =  = 1.8333...



To the right from this point on x-axis, this quadratic function increases monotonically, 

so its minimum value in the given interval/segment is at x=5, i.e. f(5).    ANSWER


Option (A).

Solved and explained.

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