SOLUTION: NASA launches a rocket at t=0 seconds. It’s height, in meters above sea level, as function of time is given by h(t)=-4.9^2+208t+339. Assuming that the rocket will splash down in

Question 1182626: NASA launches a rocket at t=0 seconds. It’s height, in meters above sea level, as function of time is given by h(t)=-4.9^2+208t+339.
Assuming that the rocket will splash down into the ocean, at what time does splashdown occur?
The rockets splashes down after ____seconds
How high above sea level does the rocket get at its peak?
The rocket peaks at _____ meters above sea level.
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
NASA launches a rocket at t=0 seconds. It’s height, in meters above sea level, as function of time is given by h(t)=-4.9t^2+208t+339.
solve by formula method the quadratic equation
Roots: 44.02, -1.57
Ignore negative
It will splash after 40.02 s
How high above sea-level does the rocket get at its peak?
Maximum height occurs when t = -b/(2a)

= -208/((2)(-4.9))
=21.22
f(21.22) = -4.9*(21.22)^2 +(208 *21.22) + 339 =2546 m
Maximum height = 2546 m above sea level

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