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A certain type of bacteria, given a favorable growth medium, doubles in population every 6.5 hours.
Given that there were approximately 100 bacteria to start with, how many bacteria will there be
after one and a half days?
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With the doubling peroiod of 6.5 hours and initial population of 100 bacteria,
the current population, as the function of time, is n(t) = 100*2^(t/6.5), where t is the time in hours.
To find the population in 1.5 days = 1.5*24 = 36 hours, the fotmula is
n(36 hours) = 100*2^(36/6.5).
Use your calculator.
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Solved.
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