SOLUTION: P(x) = x^4 + 2x^3 - 2x^2 - 3x +2 Solve for p(x) =0

Question 1180384: P(x) = x^4 + 2x^3 - 2x^2 - 3x +2
Solve for p(x) =0
Found 2 solutions by ewatrrr, MathLover1:
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!

Hi 1 and -2 are roots: Using Synthetic Division: 1 1 2 -2 -3 2 1 3 1 -2 -2 1 3 1 -2 0 -2 -2 2 1 1 -1 0 x^2 + x -1 = 0 x = .618 x = -1.618 (rounded to 4 decimal places) x = { -2, -1.618, .618, 1} Wish You the Best in your Studies.

Answer by MathLover1(20849) (Show Source): You can put this solution on YOUR website!

...factor

solutions:
=>
=>
...use quadratic formula

solutions:

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