SOLUTION: Hello there,
I'm trying to arrive at the correct answer of {±4,±i√3}. Any help would be great thank you.
Solve and express your solution in simplified form.
x^4−13x
Algebra.Com
Question 1178897: Hello there,
I'm trying to arrive at the correct answer of {±4,±i√3}. Any help would be great thank you.
Solve and express your solution in simplified form.
x^4−13x^2−48=0
Found 3 solutions by Boreal, MathLover1, Solver92311:
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
Treat this like a quadratic, since the first term is a power of 4, the middle term a power of 2 and the last term a constant.
(x^2-16)(x^2+3)=0
x=+/-4 and +/- i sqrt(3)
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!
...factor
,,,group
solutions:
if =>
if =>
if =>=> => or
so, we have:
Real solutions:
Complex solutions:
Answer by Solver92311(821) (Show Source): You can put this solution on YOUR website!
Let 
, then 
is equivalent to 
Use the quadratic formula to solve for the two values of 
. Then solve 
for each value of giving you four distinct roots as is expected from a quartic equation. Hint: 
John
My calculator said it, I believe it, that settles it
From
I > Ø
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