SOLUTION: Without expanding, find the coefficient of x^3 in the normal form of
each polynomial.
1. (3x^3+2x^2+5x+1)(x^2-3)
2. (x+1)^5
Algebra.Com
Question 1177627: Without expanding, find the coefficient of x^3 in the normal form of
each polynomial.
1. (3x^3+2x^2+5x+1)(x^2-3)
2. (x+1)^5
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!
1.
multiply and =>
2.
.....use binomial theorem
RELATED QUESTIONS
Without expanding, find the coefficient of x^3 in the normal form of
each polynomial.
(answered by josgarithmetic,ikleyn)
What is the coefficient of x^2 in the normal form of the polynomial... (answered by jim_thompson5910)
Show without expanding that x = 2 is a root of the equation
| x -6 -1 |
(answered by Edwin McCravy)
Find the normal form of each polynomial
1. (1-x-x^2) (1-x^3)
2. (1-x-x^2-x^3)... (answered by MathLover1)
Expand (1/2-2x)^5 up to the term in x^3. If the coefficient of x^2 in the expansion of... (answered by greenestamps)
Without expanding. Find the value of the determinant
|x y 1 (answered by Edwin McCravy)
Without expanding, find the value of x such that
{\det \begin{pmatrix}
2 & 3 & 1\\... (answered by ikleyn)
Suppose the product (x^2-3)(4x+2)(x+5) was expanded and written on standard form of a... (answered by MathLover1)
Evaluate each polynomial expression for the indicated value of x.
{{{2x^3-3x^2+4x}}},... (answered by jim_thompson5910)