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find 4 rational numbers such that the product of the 1st 2nd and 4th is 54. The 2nd number is 2 less than the 1st number,
the 3rd number is 5 less than the 2nd number and the 4th number is 3 less than the 3rd number
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This problem HAS NO solutions in rational numbers.
The equation is
x*(x-2)*(x-7)*(x-10) = 154,
or
x^4 - 19x^3 + 104x^2 - 140x - 154 = 0.
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| The DIAGNOSIS (obtained with special software |
| using specialized web-site) is THIS |
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Result:
The roots of the polynomial x
x^4 - 19x^3 + 104x^2 - 140x - 154
are
x1 = −0.31014
x2 = 2.63744
x3 = 6.47111
x4 = 10.20159
Explanation:
This polynomial has no rational roots that can be found using Rational Root Test.
Roots were found using quartic formulas.
So, the problem is a FAKE.
You, the visitor, simply stole my time.