SOLUTION: A rock is thrown upward from the height of 5 ft with an initial velocity of 48 ft per second. The height h(in feet) of the rock at time t seconds is h(t)=-16t^2+48t+5. When will th
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Question 1169487: A rock is thrown upward from the height of 5 ft with an initial velocity of 48 ft per second. The height h(in feet) of the rock at time t seconds is h(t)=-16t^2+48t+5. When will the ball reach a height of 8 ft?
Answer by ikleyn(52858) (Show Source): You can put this solution on YOUR website!
.
To find this time moment, solve the equation
-16t^2 + 48t + 5 = 8.
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- Introductory lesson on a projectile thrown-shot-launched vertically up
- Problem on a projectile moving vertically up and down
- Problem on an arrow shot vertically upward
- Problem on a ball thrown vertically up from the top of a tower
- Problem on a toy rocket launched vertically up from a tall platform
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