SOLUTION: 2a+3b+c/2d when a=2, b=0 c=3 and d=-5 Please help solve this problem. Thanks.

Question 11662: 2a+3b+c/2d when a=2, b=0 c=3 and d=-5
Please help solve this problem. Thanks.

Answer by glabow(165) (Show Source): You can put this solution on YOUR website!
It's not a problem if you remember: you do all grouped operations first (that's operations in parentheses), then you do all multiplies and divides, then all adds and subtracts.
There are no groups in 2a+3b+c/2d. So you do the multiplies followed by the divide.
2 x 2 + 3 x 0 + 3 / 2 x (-5) [substituting 2 for a, 0 for b, 3 for c, and -5 for d]

Or, -3 1/2

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