SOLUTION: (6x^4-15x^3+10x^2-10x+4)/(3x^2+2)

Algebra.Com
Question 1160563: (6x^4-15x^3+10x^2-10x+4)/(3x^2+2)
Answer by josgarithmetic(39630)   (Show Source): You can put this solution on YOUR website!
               2x^2    -5x      2
           ______________________________________________
3x^2+0x+2  |   6x^4   -15x^3    10x^2   -10x    4
           |
           |   6x^4    0x^3     4x^2
           |________________________
                0     -15x^3    6x^2   -10x
                      -15x^3    0x^2   -10x
                     -----------------------
                         0     6x^2     0x    4
                               6x^2     0x    4
                              ------------------
                               0        0    0

Quotient is .

RELATED QUESTIONS

12x^4-6x^3+10x ________________________... (answered by Fombitz)
10x+2=15x^2 +3x (answered by josgarithmetic)
factor 10x^2-15X^3-20X^4... (answered by jim_thompson5910)
Please help me understand to solve these problems...Algebra 2 (Factor Grouping) 1)... (answered by ikleyn)
(15X^10)%(10X^2) (answered by Alan3354)
3x+1/2... (answered by algebralearner)
{{{((6x^2-5x-4)/(6x^2+5x+1))((3x^2+7x+2)/(3x^2-10x+8))}}} (answered by math-vortex)
Factor by grouping... (answered by jim_thompson5910)
Someone please help!!! Simplify: 1/3(6x+3)-4(3x-2) A. -10x+9 B. -9x+9 C. -10x-1... (answered by jim_thompson5910)