SOLUTION: A basketball is thrown toward a hoop, which is 3m above the ground. The height (y, in metres) if the basketball above the ground after t seconds is given by the equation y= -5t^2
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-> SOLUTION: A basketball is thrown toward a hoop, which is 3m above the ground. The height (y, in metres) if the basketball above the ground after t seconds is given by the equation y= -5t^2
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Question 1159700: A basketball is thrown toward a hoop, which is 3m above the ground. The height (y, in metres) if the basketball above the ground after t seconds is given by the equation y= -5t^2 + 10t +2
A) the shot misses and the ball hits the floor. What was the hang time of the ball (that is, after how many seconds does the ball hit the ground)?
b) The player makes the she shot. How much time has passed between the throwing and the scoring
Be careful when choosing which number is the solution. The ball first reaches a height of 3m as it is traveling upwards. Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! when it hits the ground -5t^2+10t+2=0
or 5t^2-10t-2=0
t=(1/10)(10+/-sqrt(100+40))
t=(1/10) (10+/-11.83)
=2.183 seconds
The longer time is the solution for the second part, which is when -5t^2+10t+2=3
or -5t^2+10t-1=0
or 5t^2-10t+1=0
or t=(1/10)(10+/- sqrt(100-20))
the solutions are 0.106 seconds (going up) and 1.894 sec (going through rim)
