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SOLUTION: A rectangle is 8 feet longer than it is wide. the area is 65 square feet. find its dimensions.
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Question 115746
This question is from textbook
Algebra, structure and meathod, book 1
:
A rectangle is 8 feet longer than it is wide. the area is 65 square feet. find its dimensions.
This question is from textbook
Algebra, structure and meathod, book 1
Answer by
checkley71(8403)
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L=W+8
AREA=L*W
65=(W+8)W
65=W^2+8W
W^2+8W-65=0
(W+13)(W-5)=0
W-5=0
W=5 ANSWER FOR THE WIDTH
L=5+8=13 FOR THE LENGTH.
PROOF
65=5*13
65=65