SOLUTION: write the polynomial function of minimum degree in standard form that has zero -1 and 2i. Assume the leading coefficient is 1.

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Question 1155804: write the polynomial function of minimum degree in standard form that has zero -1 and 2i. Assume the leading coefficient is 1.
Found 3 solutions by MathLover1, Boreal, ikleyn:
Answer by MathLover1(20850)   (Show Source): You can put this solution on YOUR website!

function of minimum degree in standard form that has zeros

-> since complex zeros come in pairs, you also have

then


.....use the rule for difference of squares







Answer by Boreal(15235)   (Show Source): You can put this solution on YOUR website!
-2i and +2i are roots, since complex roots are conjugate
-1 is other,
(x+1)
x=2i, x= -2i. (x^2+4)=0
(x+1)(x^2+4)
x^3+x^2+4x+4=0

also,
if first coefficient is 1 then
x=(1/2)(-b+/- sqrt(b^2-4ac)
the discriminate is -16 and b is 0
therefore -4ac=-16
a is 1, c=4
(x^2+4)

Answer by ikleyn(52803)   (Show Source): You can put this solution on YOUR website!
.
write the polynomial function of minimum degree in standard form that has zero -1 and 2i. Assume the leading coefficient is 1.
~~~~~~~~~~~~~~~~~


Complex zeroes go in conjugate pairs if and only if the polynomial has real coefficients.


But the problem does not state it --- therefore both solutions of the two other tutors are IRRELEVANT.


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