SOLUTION: If a number is added to the numerator of
7
8
and twice as much is added to the denominator, the result is
8
13
.
Find the number.
Algebra.Com
Question 1153397: If a number is added to the numerator of
7
8
and twice as much is added to the denominator, the result is
8
13
.
Find the number.
Found 2 solutions by jim_thompson5910, mananth:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
x = number added to old numerator
old numerator = 7
new numerator = 7+x
old denominator = 8
new denominator = 8+2x, since twice as much is added here
old fraction =
new fraction =
new fraction = (given info)
Set equal to . Solve for x.
-------------------------
Cross multiply
Distribute
Separate out common or like terms.
Combine like terms
Divide both sides by 3
This is the answer.
-------------------------
Using that x value, we can see that,
new numerator = 7+x = 7+9 = 16
new denominator = 8+2x = 8+2*9 = 26
new fraction =
The answer is confirmed.
-------------------------
Answer: 9
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
let x be the number added to the numerator
13(7+x)=8(8+2x)
91+13x=64+16x
3x=27
x=9
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