SOLUTION: 3(x+y)^2+4(x+y)-6 when x=4 and y=-1 Please help me solve this problem.

Question 11493: 3(x+y)^2+4(x+y)-6 when x=4 and y=-1

Please help me solve this problem.
Answer by usyim88hk(158) (Show Source): You can put this solution on YOUR website!
First, make x become 4 and make y become -1 in the equation
:
3(4+(-1))^2+4(4+(-1))-6
:
all x become 4 and all y become -1, now slove it
:
3(4-1)^2+4(4-1)-6
3(3)^2+4(3)-6
3(9)+12-6
27+12-6
33
RELATED QUESTIONS
Please help me solve this problem. Okay, so You have 20-x^2 evaluate. (answered by Tyannrae,MathTherapy)

please help me solve this problem:... (answered by checkley77,jim_thompson5910)