SOLUTION: Suppose f(x,y,z) = 4x^2-3xz+2yz^2 find f(3,0,1)

SOLUTION: Suppose f(x,y,z) = 4x^2-3xz+2yz^2 find f(3,0,1)

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Question 1148180: Suppose f(x,y,z) = 4x^2-3xz+2yz^2 find f(3,0,1)
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Suppose f(x,y,z) = 4x^2-3xz+2yz^2 find f(3,0,1)
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It's substitution.
Sub 3 for x, 0 for y and 1 for z.

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